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Team:NYMU-Taipei/modeling/m6
From 2014.igem.org
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We model this part to see how the circuit works if phage is unable to control the S. mutans quorum, so the initial state of comE, the molecule that triggers the nlmC promoter, has a certain amount, which means the S. mutans is out of control. </p> | We model this part to see how the circuit works if phage is unable to control the S. mutans quorum, so the initial state of comE, the molecule that triggers the nlmC promoter, has a certain amount, which means the S. mutans is out of control. </p> | ||
<h1>System</h1> | <h1>System</h1> | ||
| + | <p>(1)$$\frac{d[luxI \; mRNA]}{dt}=P_{nlmC} \frac{[comE]^{n1}}{K_{d1}+[comE]^{n1}} (1-a)^x - K_{deg\_mluxI} [luxI \; mRNA]$$ | ||
| + | $$\frac{d[luxI]}{dt}= K_{t1} [luxI \; mRNA] - K_{deg\_luxI} [luxI]$$ | ||
| + | (2)$$\frac{d[luxR \; mRNA]}{dt}=P_{const} - K_{deg\_mluxR} [luxR \; mRNA]$$ | ||
| + | $$\frac{d[luxR]}{dt}= K_{t2} [luxR \; mRNA] - K_{deg\_luxR} [luxR]-K_{on}[AHL]^2[luxR]+K_{off}[AHLluxR]$$ | ||
| + | (3)$$\frac{d[AHL]}{dt}= K_{AHL} [luxI] +2 K_{off}[AHLluxR] -2 K_{on}[AHL]^2[luxR] - K_{deg\_AHL}$$ | ||
| + | (4)$$\frac{d[AHLluxR]}{dt}= K_{on}[AHL]^2[luxR] - K_{off}[AHLluxR]$$ | ||
| + | (5)$$\frac{d[lysine \; gene \; mRNA]}{dt}=P_{luxR} \frac{[AHLluxR]^{n2}}{K_{d2}+[AHLluxR]^{n2}} - K_{deg\_mlys} [lysine \; gene \; mRNA]$$ | ||
| + | $$\frac{d[lysine \; protein]}{dt}= K_{t2} [lysine \; gene \; mRNA] - K_{deg\_lys} [lysine \; protein]$$</p> | ||
<h1>Result</h1> | <h1>Result</h1> | ||
<h1>Reference</h1> | <h1>Reference</h1> | ||
Revision as of 15:01, 8 October 2014
Introduction
This part aims to simulate the circuit of the Target part, which will be turn on when S. mutans is too much or phage is unable to control the S. mutans quorum.
LuxI coding sequence is controlled by nlmC promoter and threshold terminator. When the quorum of S. mutans is too much, the LuxI will be expressed and generate AHL-synthase. LuxR, on the other hand, is generated by E. coli constitutively. The LuxR and AHL can form a complex that can activate the pLuxR promoter. In our design, pLuxR promoter in E. coli can activate the lysine protein that can kill S. mutans only.
We model this part to see how the circuit works if phage is unable to control the S. mutans quorum, so the initial state of comE, the molecule that triggers the nlmC promoter, has a certain amount, which means the S. mutans is out of control.
System
(1)$$\frac{d[luxI \; mRNA]}{dt}=P_{nlmC} \frac{[comE]^{n1}}{K_{d1}+[comE]^{n1}} (1-a)^x - K_{deg\_mluxI} [luxI \; mRNA]$$ $$\frac{d[luxI]}{dt}= K_{t1} [luxI \; mRNA] - K_{deg\_luxI} [luxI]$$ (2)$$\frac{d[luxR \; mRNA]}{dt}=P_{const} - K_{deg\_mluxR} [luxR \; mRNA]$$ $$\frac{d[luxR]}{dt}= K_{t2} [luxR \; mRNA] - K_{deg\_luxR} [luxR]-K_{on}[AHL]^2[luxR]+K_{off}[AHLluxR]$$ (3)$$\frac{d[AHL]}{dt}= K_{AHL} [luxI] +2 K_{off}[AHLluxR] -2 K_{on}[AHL]^2[luxR] - K_{deg\_AHL}$$ (4)$$\frac{d[AHLluxR]}{dt}= K_{on}[AHL]^2[luxR] - K_{off}[AHLluxR]$$ (5)$$\frac{d[lysine \; gene \; mRNA]}{dt}=P_{luxR} \frac{[AHLluxR]^{n2}}{K_{d2}+[AHLluxR]^{n2}} - K_{deg\_mlys} [lysine \; gene \; mRNA]$$ $$\frac{d[lysine \; protein]}{dt}= K_{t2} [lysine \; gene \; mRNA] - K_{deg\_lys} [lysine \; protein]$$
Result
Reference
method
result
Reference
