Team:NYMU-Taipei/modeling/m1

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       <p>    Without S. mutans, other bacteria will grow rampantly, so we build a model to demonstrate the multi-species competition of dental plaque bacterium.</p>
       <p>    Without S. mutans, other bacteria will grow rampantly, so we build a model to demonstrate the multi-species competition of dental plaque bacterium.</p>
       <h1>system</h1>
       <h1>system</h1>
 +
      <p>$$a$$</p>
       <p>$$\frac{dx_i}{dt} = \mu_x_i \times x_i = \left({\mu_\max_i}\frac{s}{k_s+s}-k_d_i\right) \times x_i$$</p>
       <p>$$\frac{dx_i}{dt} = \mu_x_i \times x_i = \left({\mu_\max_i}\frac{s}{k_s+s}-k_d_i\right) \times x_i$$</p>
 +
      <p>$$\frac{dx_i}{dt} = \mu_x_i \times x_i = ({\mu_\max_i}\frac{s}{k_s+s}-k_d_i) \times x_i$$</p>
       <h1>result</h1>
       <h1>result</h1>
       <h1>discussion</h1>
       <h1>discussion</h1>
   </div>
   </div>
</html>
</html>

Revision as of 10:24, 5 August 2014

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competition model

purpose & introduction

Why not kill all S. mutans in our cavity?

Without S. mutans, other bacteria will grow rampantly, so we build a model to demonstrate the multi-species competition of dental plaque bacterium.

system

$$a$$

$$\frac{dx_i}{dt} = \mu_x_i \times x_i = \left({\mu_\max_i}\frac{s}{k_s+s}-k_d_i\right) \times x_i$$

$$\frac{dx_i}{dt} = \mu_x_i \times x_i = ({\mu_\max_i}\frac{s}{k_s+s}-k_d_i) \times x_i$$

result

discussion