Team:ETH Zurich/labblog/20140824mod

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(Monday, August 24th)
(Monday, August 24th)
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$$\frac{d[GFP]}{dt}=\frac{k_{45}[P_{tot}]\Big(-1+\sqrt{1+8\frac{AHL_i}{K_{d3}}}\Big)^2}{16\frac{K_{d4}}{K_{d3}}+\Big(-1+\sqrt{1+8\frac{AHL_i}{K_{d3}}}\Big)^2}-d_{GFP}[GFP]$$.
$$\frac{d[GFP]}{dt}=\frac{k_{45}[P_{tot}]\Big(-1+\sqrt{1+8\frac{AHL_i}{K_{d3}}}\Big)^2}{16\frac{K_{d4}}{K_{d3}}+\Big(-1+\sqrt{1+8\frac{AHL_i}{K_{d3}}}\Big)^2}-d_{GFP}[GFP]$$.
For very high initial concentrations AHLi, we have  
For very high initial concentrations AHLi, we have  
-
$$\frac{d[GFP]}{dt}={k_{45}[P_{tot}]-d_{GFP}[GFP]$$
+
$$\frac{d[GFP]}{dt}=k_{45}[P_{tot}]-d_{GFP}[GFP]$$
  so by taking $$t_{1/2}=\frac{ln(2)}{d_{GFP}}$$ from experimental curves, we are able to retrieve $$d_{GFP} = 4.9 . 10^{-3} min^{-1}$$.
  so by taking $$t_{1/2}=\frac{ln(2)}{d_{GFP}}$$ from experimental curves, we are able to retrieve $$d_{GFP} = 4.9 . 10^{-3} min^{-1}$$.
For very low initial concentrations of initial AHL and considering degradation, we have  
For very low initial concentrations of initial AHL and considering degradation, we have  

Revision as of 19:53, 11 October 2014