Team:TU Delft-Leiden/Modeling/Landmine

Landmine Module

An important part of our iGEM project is a promoter sensitive to landmines, first described by Yagur-Kroll et al. [1]. We will use two of the promoters described in this paper, ybiJ and ybiFB2A1, in our project. Of these promoters, not much is known other than the fact that they have a DNT/TNT-dependent response curve (see figure 1). Our goal was to find a model which would be able to reproduce the response curves of both promoters.

Our first approach was to solve a system of Ordinary Differential Equations (ODEs) resembling the transcription and translation of a gene activated by the DNT-sensitive promoter. The ODEs were derived from the following system of reactions: $$ P_{R} + DNT \ \overset{k_{on}}{\underset{k_{off}}{\rightleftharpoons}} \ P_{A} \tag{1}$$ $$ P_{A} \ \xrightarrow{s_{A}} \ P_{A} + mRNA \tag{2}$$ $$ P_{R} \ \xrightarrow{s_{R}} \ P_{R} + mRNA \tag{3} $$ $$ mRNA \ \xrightarrow{s_{P}} \ mRNA + R \tag{4} $$ $$ mRNA \ \xrightarrow{d_{M}} \ \emptyset \tag{5} $$ $$ R\ \xrightarrow{d_{P}} \ \emptyset \tag{6} $$ In these reaction equations, \(P_{R}\) and \(P_{A}\) indicate respectively repressed and active promoters. DNT indicates DNT molecules, mRNA stands for an mRNA molecule transcribed from the gene behind the promoter and R is the reporter protein which is translated from the mRNA. \(k_{on}\) and \(k_{off}\) are the rates at which a promoter goes from the repressed to the active state and vice versa. \(s_{A}\) is the transcription rate from an active promoter. \(s_{R}\) is the transcription rate from a repressed promoter; this is also referred to as leakage. \(s_{P}\) is the translation rate. \(d_{M}\) and \(d_{P}\) are the mRNA and protein degradation rates.

Reaction (1) describes the activation and deactivation of a promoter in the presence of DNT. We assume that the activation mechanism can be described as the binding of the DNT to the repressed promoter, with the resulting complex being an active promoter. Reaction (2) describes transcription. Reaction (3) described transcription through leakage, i.e. transcription from a repressed promoter. Reaction (4) describes translation. Reactions (5) and (6) describe mRNA and reporter protein degradation respectively.

This system of reactions leads to the following system of ODEs: $$ \frac{d}{dt} [P_{R}] = \ -k_{on}[P_{R}][DNT] \ + \ k_{off}[P_{A}] \tag{7.1} $$ $$ \frac{d}{dt} [P_{A}] = \ k_{on}[P_{R}][DNT] \ - \ k_{off}[P_{A}] \tag{7.2} $$ $$ \frac{d}{dt} [DNT] = \ -k_{on}[P_{R}][DNT] \ + \ k_{off}[P_{A}] \tag{7.3} $$ $$ \frac{d}{dt} [mRNA] = \ s_{A}[P_{A}] \ + \ s_{R}[P_{R}] \ - \ d_{M}[mRNA] \tag{7.4} $$ $$ \frac{d}{dt} [R] = \ s_{P}[mRNA] \ - \ d_{P}[R] \tag{7.5} $$ A system of ordinary differential equations like this can be solved numerically, with the MATLAB function ode45. The result of this will be a set of curves describing the concentration of each compound in time. However, when choosing parameters with an realistic order of magnitude, the time needed to reach steady state, i.e. when the reporter protein concentration does not change anymore, is so long that the script turns extremely computationally intensive. Because time-dependence is not relevant when imitating the dose-response curves from the Yagur-Kroll paper [1], we decided to discard the ODE method and switch to analytic steady state methods.

The goal of this steady state approach is to find a relation between the concentration of reporter protein ([R]) and the amount of DNT ([DNT]), with as few parameters as possible. To obtain such a relation, we started from equation (7.2), which describes the change in time of the concentration of activated promoters. We used a steady state assumption to simplify this relationship, which means that we assumed that the concentration of active promoters does not change in time, i.e \(\frac{d}{dt} [P_{A}] = \ 0\). This assumption can be justified by examining the experimental data in figure 2, from which it can be clearly seen that after a certain amount of time, the reporter protein level reaches a constant value.

This yields the following: $$ [P_{A}] = \ \frac{k_{on}}{k_{off}}[P_{R}][DNT] = \ \frac{1}{K_{d}}[P_{R}][DNT] \tag{8} $$ Here we introduced the dissociation constant \(K_{d} = \ \frac{k_{on}}{k_{off}}\). The next assumption we make is that the total amount of promoter (\([P_{T}\)) is constant. This makes sense, since an active promoter can become a repressed promoter and vice versa, but it is not possible to make new promoters or let promoters vanish. We ignore and therefore neglect the fact that during cell replication, the promoter level will rise due to DNA replication. However, we assume that this is a minor contribution. This assumption yields the following: $$ [P_{T}] = \ [P_{A}] + \ [P_{R}] \ \rightarrow \ [P_{R}] = \ [P_{T}] - \ [P_{A}] \tag{9} $$ Combining equations (8) and (9), we obtain: $$ [P_{A}] = \ \frac{1}{K_{d}}([P_{T}] - \ [P_{A}])[DNT] \tag{10} $$ This can be rewritten to the following form: $$ \frac{[P_{A}]}{[P_{T}]} = \ \frac{[DNT]}{K_{D} + \ [DNT]} \tag{11} $$ Equation (11) thus gives us the number of active promoters as a fraction of the total amount of promoters.

The change of concentration of reporter protein ([R]) is given by the following ODE: $$ \frac{d}{dt} [R] = \ \frac{[P_{A}]}{[P_{T}]}k_{1} + \ \frac{[P_{R}]}{[P_{T}]}k_{2} - \ d_{p}[R] \tag{12} $$