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Team:HokkaidoU Japan/Project/Modeling
From 2014.igem.org
(Difference between revisions)
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\left[ \frac{\sigma_i}{2}~,~\frac{\sigma_j}{2} \right] = i\varepsilon_{ijk} \frac{\sigma_k}{2} \] | \left[ \frac{\sigma_i}{2}~,~\frac{\sigma_j}{2} \right] = i\varepsilon_{ijk} \frac{\sigma_k}{2} \] | ||
| + | \[ \] | ||
| + | |||
| + | \begin{cases} | ||
| + | \dot{X}=a_X-k_{bind}XY+k_{bind}Z-b_XX & \\ | ||
| + | \dot{Y}=a_Y-k_{bind}XY+k_{bind}Z-b_YY & \\ | ||
| + | \dot{Z}=k_{bind}XY-k_{bind}Z-b_ZZ & | ||
| + | \end{cases} | ||
</html> | </html> | ||
Latest revision as of 03:51, 27 September 2014
\[ \zeta(s) = \sum_{n=1}^\infty\frac{1}{n^s} \] \[ \sigma_1 = \left( \matrix{ 0 & 1 \cr 1 & 0 } \right), \sigma_2 = \left( \matrix{ 0 & -i \cr i & 0 } \right), \sigma_3 = \left( \matrix{ 1 & 0 \cr 0 & -1} \right) は,以下の式を満たす. \left[ \frac{\sigma_i}{2}~,~\frac{\sigma_j}{2} \right] = i\varepsilon_{ijk} \frac{\sigma_k}{2} \] \[ \] \begin{cases} \dot{X}=a_X-k_{bind}XY+k_{bind}Z-b_XX & \\ \dot{Y}=a_Y-k_{bind}XY+k_{bind}Z-b_YY & \\ \dot{Z}=k_{bind}XY-k_{bind}Z-b_ZZ & \end{cases}
