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Team:ETH Zurich/test
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| - | < | + | <head><link rel="stylesheet" href="https://2014.igem.org/Team:ETH_Zurich/css/katex.min.css?action=raw&ctype=text/css" type="text/css"/></head> |
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| - | {{ | + | <span class="equation">\displaystyle c = \pm\sqrt{a^2 + b^2}</span> |
| + | <div class="equation"> \displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }</div> | ||
| + | <div class="equation"> \displaystyle \left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right) </div> | ||
| + | <div class="equation">f(x) = \int_{-\infty}^\infty | ||
| + | \hat f(\xi)\,e^{2 \pi i \xi x} | ||
| + | \,d\xi | ||
| + | </div> | ||
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Latest revision as of 19:22, 18 September 2014
\displaystyle c = \pm\sqrt{a^2 + b^2}
\displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }
\displaystyle \left( \sum_{k=1}^n a_k b_k \right)^2 \leq \left( \sum_{k=1}^n a_k^2 \right) \left( \sum_{k=1}^n b_k^2 \right)
f(x) = \int_{-\infty}^\infty
\hat f(\xi)\,e^{2 \pi i \xi x}
\,d\xi
