Team:ETH Zurich/modeling/qs

From 2014.igem.org

(Difference between revisions)
(Retrieving degradation rates)
(Retrieving degradation rates)
Line 199: Line 199:
$$\frac{d[GFP]}{dt}=LeakyLux+\frac{k_{mRNAGFP} k_{GFP} \alpha_{LuxR}^2}{d_{LuxR}^2(Km_{Lux}^2+\alpha_{LuxR})}-d_{GFP}[GFP]$$
$$\frac{d[GFP]}{dt}=LeakyLux+\frac{k_{mRNAGFP} k_{GFP} \alpha_{LuxR}^2}{d_{LuxR}^2(Km_{Lux}^2+\alpha_{LuxR})}-d_{GFP}[GFP]$$
-
so by taking $$t_{1/2}=\frac{ln(2)}{d_{GFP}}$$ from experimental curves, we find $$d_{GFP} = 4.9 . 10^{-3} min^{-1}$$.
+
so by taking  
 +
$$t_{1/2}=\frac{ln(2)}{d_{GFP}}$$
 +
from experimental curves, we find  
 +
$$d_{GFP} = 4.9 . 10^{-3} min^{-1}$$
Line 206: Line 209:
and thus a steady state
and thus a steady state
-
$$[GFP]=Constant*\frac(d_{GFP}-2d_{AHL})}(e^{-2d_{AHL}t}-e^{-d_{GFP}t})$$
+
$$[GFP]=Constant*\frac{1}{(d_{GFP}-2d_{AHL})}(e^{-2d_{AHL}t}-e^{-d_{GFP}t})$$
  This curve has a maximum at  
  This curve has a maximum at  

Revision as of 03:01, 17 October 2014

iGEM ETH Zurich 2014